Fehlerkorrektur Multiplikation komplexer Zahlen (Polarform)

master
Marco Remy 7 years ago
parent 294948b91c
commit 61d767bd71

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@ -449,7 +449,7 @@ $a = 0, b = 0 $ & $\varphi = 0^\circ $ & $\varphi = 0 $ \\
\end{align*}
\begin{align*}
{ z }_{ 1 }\cdot { z }_{ 2 } & =\left| { z }_{ 1 } \right| \left( \cos { \left( { \varphi }_{ 1 } \right) } +\sin { \left( { \varphi }_{ 1 } \right) } i \right) \cdot \left| { z }_{ 2 } \right| \left( \cos { \left( { \varphi }_{ 2 } \right) } \cdot \sin { \left( { \varphi }_{ 2 } \right) } i \right) \\
& =\left| { z }_{ 1 } \right| \cdot \left| { z }_{ 2 } \right| \left( \cos { \left( { \varphi }_{ 1 } \right) \cdot \cos { \left( { \varphi }_{ 2 } \right) } } +\sin { \left( { \varphi }_{ 1 } \right) } \cdot \sin { \left( { \varphi }_{ 2 } \right) } i \right)
& =\left| { z }_{ 1 } \right| \cdot \left| { z }_{ 2 } \right| \left( \cos { \left( { \varphi }_{ 1 } + { \varphi }_{ 2 } \right) } +\sin { \left( { \varphi }_{ 1 } + { \varphi }_{ 2 } \right) } i \right)
\end{align*}
\textbf{Division}

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